E.多重映射

解题思路

• 对集合进行整体操作，集合大小只增不减，问最后集合标号
• 维护集合，考虑并查集
• 但直接用并差集维护会有以下问题：
• 当前集合变标号，可能会和之前标号相同，则进行并查集操作时，会接上之前的变换
• 为消除其影响，考虑加入时间戳，后面新产生的标号与之前的不同
• 进行操作时，若没有则跳过
• 若没有，则产生新的集合，对应的时间戳
• 若有，则合并集合，时间戳不变
• 
• 时，带上时间戳

import java.io.*;
import java.math.BigInteger;
import java.util.Arrays;
import java.util.HashMap;
import java.util.HashSet;
import java.util.Objects;
import java.util.PriorityQueue;
import java.util.Stack;
import java.util.StringTokenizer;//implements Runnable
public class Main{static long md=(long)998244353;static long Linf=Long.MAX_VALUE/2;static int inf=Integer.MAX_VALUE/2;static int N=2000000;static int n=0;static int m=0;static class Node{int x;int y;public Node(int u,int v) {x=u;y=v;}@Overridepublic boolean equals(Object o) {if (this == o) return true;if (o == null || getClass() != o.getClass()) return false;Node may = (Node) o;return x == may.x && y==may.y;}@Overridepublic int hashCode() {return Objects.hash(x, y);}}static HashMap<Node, Node> fa=new HashMap<Node, Node>();static Node find(Node x) {//跟正常并查集一样if(x.x==fa.get(x).x&&x.y==fa.get(x).y)return x;else {Node f=fa.get(x);Node ff=find(f);fa.put(f, ff);return ff;}}static int[] a=new int[N+1];static int[] x=new int[N+1];static int[] y=new int[N+1];static boolean[] hs=new boolean[N+1];static int[] t=new int[N+1];public static void main(String[] args) throws Exception{AReader input=new AReader();PrintWriter out = new PrintWriter(new OutputStreamWriter(System.out));	int T=input.nextInt();while(T>0) {n=input.nextInt();m=input.nextInt();for(int i=1;i<=n;++i) {a[i]=input.nextInt();Node ro=new Node(a[i], 0);fa.put(ro, ro);//初始化，重复添无影响hs[a[i]]=true;}for(int i=1;i<=m;++i) {x[i]=input.nextInt();y[i]=input.nextInt();Node lo=new Node(x[i], 0);Node ro=new Node(y[i], 0);fa.put(lo, lo);fa.put(ro, ro);//初始化，重复添无影响}
//			out.print(fa.get(new Node(1, 0)));for(int i=1;i<=m;++i) {int l=x[i];int r=y[i];if(!hs[l])continue;if(!hs[r]) {//与之前区别t[r]++;}hs[l]=false;hs[r]=true;Node lo=new Node(l, t[l]);Node ro=new Node(r, t[r]);fa.put(lo, ro);
//				out.print(fa.get(ro));fa.put(ro, ro);//集合头自己指自己，初始化，重复添无影响}//			out.print(fa.get(new Node(1, 0)));for(int i=1;i<=n;++i) {Node fx=find(new Node(a[i], 0));out.print(fx.x+" ");}out.println();//清空for(int i=1;i<=n;++i) {hs[a[i]]=false;t[a[i]]=0;}for(int i=1;i<=m;++i) {hs[x[i]]=false;t[x[i]]=0;hs[y[i]]=false;t[y[i]]=0;}fa.clear();T--;}out.flush();out.close();}
//	public static final void main(String[] args) throws Exception {
//		  new Thread(null, new Main(), "线程名字", 1 << 27).start();
//	}
//		@Override
//		public void run() {
//			try {
//				//原本main函数的内容
//				solve();
//
//			} catch (Exception e) {
//			}
//		}staticclass AReader{ BufferedReader bf;StringTokenizer st;BufferedWriter bw;public AReader(){bf=new BufferedReader(new InputStreamReader(System.in));st=new StringTokenizer("");bw=new BufferedWriter(new OutputStreamWriter(System.out));}public String nextLine() throws IOException{return bf.readLine();}public String next() throws IOException{while(!st.hasMoreTokens()){st=new StringTokenizer(bf.readLine());}return st.nextToken();}public char nextChar() throws IOException{//确定下一个token只有一个字符的时候再用return next().charAt(0);}public int nextInt() throws IOException{return Integer.parseInt(next());}public long nextLong() throws IOException{return Long.parseLong(next());}public double nextDouble() throws IOException{return Double.parseDouble(next());}public float nextFloat() throws IOException{return Float.parseFloat(next());}public byte nextByte() throws IOException{return Byte.parseByte(next());}public short nextShort() throws IOException{return Short.parseShort(next());}public BigInteger nextBigInteger() throws IOException{return new BigInteger(next());}public void println() throws IOException {bw.newLine();}public void println(int[] arr) throws IOException{for (int value : arr) {bw.write(value + " ");}println();}public void println(int l, int r, int[] arr) throws IOException{for (int i = l; i <= r; i ++) {bw.write(arr[i] + " ");}println();}public void println(int a) throws IOException{bw.write(String.valueOf(a));bw.newLine();}public void print(int a) throws IOException{bw.write(String.valueOf(a));}public void println(String a) throws IOException{bw.write(a);bw.newLine();}public void print(String a) throws IOException{bw.write(a);}public void println(long a) throws IOException{bw.write(String.valueOf(a));bw.newLine();}public void print(long a) throws IOException{bw.write(String.valueOf(a));}public void println(double a) throws IOException{bw.write(String.valueOf(a));bw.newLine();}public void print(double a) throws IOException{bw.write(String.valueOf(a));}public void print(char a) throws IOException{bw.write(String.valueOf(a));}public void println(char a) throws IOException{bw.write(String.valueOf(a));bw.newLine();}}}